81 m/s^2), and s is the displacement (height above the building).
0 = 80^2 + 2(-9.81)s
Solving for s, we get:
s = \frac{80^2}{2(9.81)} = 325.87 m
So, the maximum height reached by the ball above the building is:
325.87 - 90 = \boxed{235.87 \text{ m}}
b)
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