A ball (m= 0.4kg) is moving toward a wall ( V1 = 10 m/s) and after a collision, will return with V2 = 8 m/s ( Opposite direction) What is the impulse force (F) if the collision time was t = 0.001 s F = 800 N F = - 800 N F = -7200 N F = 7200 N
Added by Eugene D.
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Change in velocity, \(\Delta V = V_2 - V_1 = -8 - 10 = -18 m/s\). Show more…
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