A ball of mass 0.100 kg moving with a speed of 2.12 m/s hits a wall and bounces back with a speed of 1.00 m/s in the opposite direction. What is the change in the ball's kinetic energy?
Added by Juan Francisco Z.
Step 1
Given: Mass (m) = 0.100 kg Initial velocity (u) = 2.12 m/s Initial kinetic energy (KE_initial) = 0.5 * mass * (initial velocity)^2 KE_initial = 0.5 * 0.100 kg * (2.12 m/s)^2 KE_initial = 0.5 * 0.100 kg * 4.4944 m^2/s^2 KE_initial = 0.22472 J Show more…
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