Question

6. A ball of mass 1.80 kg is released from rest at a height of h=0.650 m above a vertical spring of force constant k as shown. The ball strikes the top of the spring and compresses it a distance of 0.0900 m. Find (a) the speed of the ball just as it touches the spring and (b) the force constant of the spring, k. There are 3 positions, A, B, and C You can go from A to B and then again from A to C Answers (a) 3.57 m/s (b) 3220 N/m

          6. A ball of mass 1.80 kg is released from rest at a height of h=0.650 m above
a vertical spring of force constant k as shown. The ball strikes the top of
the spring and compresses it a distance of 0.0900 m. Find (a) the speed of
the ball just as it touches the spring and (b) the force constant of the spring,
k.
There are 3 positions, A, B, and C
You can go from A to B and then again from A to C
Answers (a) 3.57 m/s (b) 3220 N/m

6. A ball of mass 1.80 kg is released from rest at a height of h=0.650 m above
a vertical spring of force constant k as shown. The ball strikes the top of
the spring and compresses it a distance of 0.0900 m. Find (a) the speed of
the ball just as it touches the spring and (b) the force constant of the spring,
k.
There are 3 positions, A, B, and C
You can go from A to B and then again from A to C
Answers (a) 3.57 m/s (b) 3220 N/m

Added by Sophia P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

02/27/2023

Step 1

The potential energy (PE) is given by the formula: PE = m * g * h where m is the mass of the ball (1.80 kg), g is the acceleration due to gravity (9.81 m/s²), and h is the height (0.650 m). PE = 1.80 kg * 9.81 m/s² * 0.650 m = 11.47 J (Joules) (a) When the Show more…

Show all steps