A ball rolls along a smooth horizontal floor at 10 m/s, then starts up a 20° ramp. How high does it go before rolling back down?
Added by Deanna J.
Step 1
First, we need to find the vertical component of the initial velocity. We can use the formula: $v_y = v \sin(\theta)$, where $v_y$ is the vertical component, $v$ is the initial velocity, and $\theta$ is the angle of the ramp. Show more…
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A ball rolls along a smooth horizontal floor at $10 \mathrm{m} / \mathrm{s}$, then starts up a $20^{\circ}$ ramp. How high does it go before rolling back down?
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