Given the pole strength $p = 50 A m$ and the length of the magnet $l = 0.1 m$, we can find the magnetic moment:
$m = pl = 50 A m \times 0.1 m = 5 A m^2$
Now, we can plug in the values into the formula:
$B = \dfrac{4\pi \times 10^{-7} Tm/A}{4\pi} \dfrac{2(5 A
Show more…