"A bar of iron is 10 cm at 20°C. At 19°C, it will be (Take, a of iron = 11 × 10? 6°C?1 ) (a) 11 10 cm × ? 6 , longer (b) 11 10 × ? 5 cm, shorter (c) 11 10 × ? 6 cm, shorter (d) 11 10 × ? 5 cm, longer"
Added by Ram M.
Step 1
Step 1:** Given data: Initial length of iron bar, L = 10 cm Initial temperature, T1 = 20°C Final temperature, T2 = 19°C Temperature coefficient of iron, α = 11 × 10^-6 °C^-1 ** Show more…
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A bar of iron is $10 \mathrm{~cm}$ at $20^{\circ} \mathrm{C}$. At $19^{\circ} \mathrm{C}$ it will be $(\alpha$ of iron $\left.=11 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right)$ (a) $11 \times 10^{-6} \mathrm{~cm}$ longer (b) $11 \times 10^{-6} \mathrm{~cm}$ shorter (c) $11 \times 10^{-5} \mathrm{~cm}$ shorter (d) $11 \times 10^{-5} \mathrm{~cm}$ longer
Heat and Kinetic Theory of Gases
Round 1
1065: An iron bar of length 10m is heated from 0°C to 100°C. If the coefficient of linear thermal expansion of iron is [{10 × 10^-6} / C] the increase in the length of bar is (A) 0.5 cm (B) 1.0 cm (C) 1.5 cm (D) 2.0 cm
Kajal R.
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