Since the growth is exponential, we can model the value as $V(t) = V_0 e^{kt}$, where $V_0$ is the initial value and $k$ is the exponential growth rate.
We are given that $V_0 = 264$.
In 1979, $t=0$, so $V(0) = 264$.
In 1989, $t=10$, and $V(10) = 438$.
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