00:01
Hello, here we have to solve the given problem, and first we have to calculate the horizontal and vertical components of the initial velocity.
00:07
Let's redraw this vector, v0, and let's introduce y and x, x, x.
00:18
So that's the angle alpha, and this is v0 x, and this is v0y.
00:25
As we can see, v0x equals to v0 multiplied by cosine alpha, and v0y, equals to v0 multiplied by sine alpha.
00:35
Let's calculate v0 x, and that equals to 6 .5 meters per second, multiplied by cosine of 49 degree.
01:08
That equals to 4 .26 meters per second, that is roughly 4 .3 meters per second.
01:18
Now, let's calculate v0y, and that equals to 6.
01:23
5 meters per second times sign of 49 degree.
01:35
That equals to 4 .91 meters per second.
01:40
That is roughly 4 .9 meters per second.
01:46
Now we have to show that the time taken to reach the basket is exactly 0 .69 seconds.
02:00
Let's do this.
02:03
There is only one force which is exerted in the system and that is gravity.
02:08
That's why vx is constant and that equals to v0x.
02:14
Therefore the distance traveled in the x direction l equals to, which is 2 .9 meters, equals to v0x multiplied by time of the flight and that is v0 cosine alpha multiply by time of the flight.
02:38
Therefore, time of the flight equals to l divided by v0 cosine alpha, that is 2 .9 meters divided by r.
02:56
This velocity with speed which we've already calculated...