A battery has emf 30.0 V and internal resistance r.r. A 9.00 Ω9.00 Ω resistor is connected to the terminals of the battery, and the voltage drop across the resistor is 27.0 V. What is the internal resistance of the battery?
Added by Curtis S.
Step 1
This can be expressed as: E = Vr + Vint where E is the emf of the battery, Vr is the voltage across the external resistor, and Vint is the voltage across the internal resistance. We know that E = 30.0 V and Vr = 27.0 V. So we can solve for Vint: Vint = E - Vr Show more…
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