00:01
In this problem, we are given that there is a circuit in which we have a resistor whose resistances are and a capacitor whose capacitance is c.
00:11
And we have a switch here that's represented with the letter s and we have a voltage source whose potential difference is v.
00:19
And it is given that when t is zero, the switch s is closed.
00:26
And as a result, the circuit is complete.
00:27
So we need to determine first the charge on capacitor when t is tending to infinity.
00:37
So that's after a very long time.
00:39
So to get the charge, we'll simply use this equation and let's plug in the value of t as infinity here.
00:46
So we would get the charge q, which is as a function of time t.
00:49
So after a long time, that would be q0 into one minus, e -raise 2 minus infinity by our so that's just going to give us the value zero because we know that e raise to minus infinity.
01:05
This is zero.
01:08
So we'll substitute the value of e raise to minus infinity as zero here.
01:12
So that will give us the charge as just q0 and q0 that's the initial charge here...