A bead moves along a straight 60-mm wire that lies along the x-axis. The position of the bead is

So we're considering the function F of T equals sine of pi T over two. I advise that you graph t

Question

A bead moves along a straight \( 60-\mathrm{mm} \) wire that lies along the \( x \)-axis. The position of the bead is given by \[ x=2 t^{2}-10 t \mathrm{~mm} \] Where \( x \) is measured from the center of the ruire, and \( t \) is the time in seconds. Determine (a) the time when the bead leaves the wire: and (b) the distance traveled by the bead from \( t=0 \) until it leaves the wire.

          A bead moves along a straight \( 60-\mathrm{mm} \) wire that lies along the \( x \)-axis. The position of the bead is given by
\[
x=2 t^{2}-10 t \mathrm{~mm}
\]

Where \( x \) is measured from the center of the ruire, and \( t \) is the time in seconds. Determine (a) the time when the bead leaves the wire: and (b) the distance traveled by the bead from \( t=0 \) until it leaves the wire.

A bead moves along a straight 60-mm wire that lies along the x-axis. The position of the bead is given by

x=2 t^2-10 t mm

Where x is measured from the center of the ruire, and t is the time in seconds. Determine (a) the time when the bead leaves the wire: and (b) the distance traveled by the bead from t=0 until it leaves the wire.

Added by Karen F.

Practice Problem in Physics for the JEE Main and Advanced

Abhay Kumar 2015 Edition

Chapter 3

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A bead moves along a straight \( 60-\mathrm{mm} \) wire that lies along the \( x \)-axis. The position of the bead is given by \[ x=2 t^{2}-10 t \mathrm{~mm} \] Where \( x \) is measured from the center of the ruire, and \( t \) is the time in seconds. Determine (a) the time when the bead leaves the wire: and (b) the distance traveled by the bead from \( t=0 \) until it leaves the wire.