Question

9 mm 232 250 ?. A. 6.7 9 mm ?c ?max ?? 200 (a) Section (b) Bending stress (c) Shear stress

          9 mm
232
250 ?.
A.
6.7
9 mm
?c
?max
??
200
(a) Section
(b) Bending stress (c) Shear stress

Added by Matthew R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

Step 1

The area of the flanges (Aflange) can be calculated by multiplying the width (200 mm) by the thickness (9 mm) of the flanges: Aflange = 200 mm * 9 mm = 1800 mm^2 The area of the web (Aweb) can be calculated by subtracting the area of the flanges from the total Show more…

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A beam of I section is 200 mm wide and 250 mm deep as shown in the figure below. It is subjected to a bending moment of 'M' and shear force 'V'. Determine the proportion in which the flanges (together) and web resist (i) bending moment of 'M', (ii) shear force 'V'. (Ans: Vweb = 96.65% of V, Mweb = 11.76% of M) 9 mm 250 N 232 6.7 wu 6 Ot 200 a Section b Bending stress c Shear stress