Question

A beam of length 6 m is simply supported at its ends and carries two-point loads of 48 kN and 40 kN at a distance of 1 m and 3 m respectively from the left support. Calculate the deflection under each load using. Macaulay’s method. Find also the maximum deflection. Given E = 2 × 10? N/mm² and I = 85 × 10? mm?.

Name: A beam of length 6 m is simply supported at its ends and carries two-point loads of 48 kN and 40 kN at a distance of 1 m and 3 m respectively from the left support. Calculate the deflection under each load using. Macaulay’s method. Find also the maximum deflection. Given E = 2 × 10? N/mm² and I = 85 × 10? mm?.
Uploaded: 2024-12-22T03:59:58-08:00
Duration: 1 min 51 s
Channel: Lien Le
Description: A beam of length 6 m is simply supported at its ends and carries two-point loads of 48 kN and 40 kN at a distance of 1 m and 3 m respectively from the left support. Calculate the deflection under each load using. Macaulay’s method. Find also the maximum deflection. Given E = 2 × 10? N/mm² and I = 85 × 10? mm?.

          A beam of length 6 m is simply supported at its ends and carries two-point loads of 48 kN and 40 kN at a distance of 1 m and 3 m respectively from the left support. Calculate the deflection under each load using. Macaulay’s method. Find also the maximum deflection. Given E = 2   × 10? N/mm² and I = 85 × 10? mm?.

A beam of length 6 m is simply supported at its ends and carries two-point loads of 48 kN and 40 kN at a distance of 1 m and 3 m respectively from the left support. Calculate the deflection under each load using. Macaulay’s method. Find also the maximum deflection. Given E = 2 × 10? N/mm² and I = 85 × 10? mm?.

Added by Drew P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Lien Le

12/22/2024

Step 1

Let \( R_A \) and \( R_B \) be the reactions at the left and right supports, respectively. Using the moment equilibrium about point A: \[ R_B \times 6 = 48 \times 1 + 40 \times 3 \] \[ R_B \times 6 = 48 + 120 = 168 \, \text{kN} \] \[ R_B = \frac{168}{6} = 28 Show more…

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