Question

A beam of protons is accelerated from rest through a potential difference of 2000 V and then enters a uniform magnetic field which is perpendicular to the direction of the proton beam. If the flux density is 0.4 T, calculate the radius of the path which the beam describes. (Proton mass = 1.7 x 10^-27 kg, Electronic charge = 1.6 x 10^-19 C)

Name: a beam of protons is accelerated form rest through a potential difference of 2000 v and then enters a uniform magnetic field which is perpendicular to the direction of the proton beam if the 40743
Uploaded: 2022-07-28T18:06:29-08:00
Duration: 4 min 2 s
Channel: Adi S
Description: a beam of protons is accelerated form rest through a potential difference of 2000 v and then enters a uniform magnetic field which is perpendicular to the direction of the proton beam if the 40743

          A beam of protons is accelerated from rest through a potential difference of 2000 V and then enters a uniform magnetic field which is perpendicular to the direction of the proton beam. If the flux density is 0.4 T, calculate the radius of the path which the beam describes. (Proton mass = 1.7 x 10^-27 kg, Electronic charge = 1.6 x 10^-19 C)

Added by William W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Adi S

07/28/2022

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We need to calculate the radius of the path described by a beam of protons that is accelerated through a potential difference and then enters a perpendicular magnetic field. The given values are the potential difference (2000 V), the magnetic flux density (0.4 T), Show more…

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A beam of protons is accelerated from rest through a potential difference of 2000 V and then enters a uniform magnetic field which is perpendicular to the direction of the proton beam. If the flux density is 0.4 T, calculate the radius of the path which the beam describes. (Proton mass = 1.7 x 10^-27 kg, Electronic charge = 1.6 x 10^-19 C)