00:03
Hello, here we have to solve the following problem.
00:06
The beam of protons is direct the strength along the positive y direction.
00:11
Let's start drawing this system.
00:14
We will first sketch the coordinate axis, that x and y.
00:25
And here the protons have the initial velocity in that direction.
00:36
So let's sketch this proton.
00:38
It has a positive charge.
00:39
And v0 is upwards.
00:45
Actually here that is v and this velocity v is 7 .1 times 10 power by 5 meter the electric field has a magnitude of 390 volt per meter and it is a negative y direction.
01:12
We have to determine the magnitude of the magnetic volt per meter.
01:12
And it is a negative y direction.
01:23
We have to determine the magnitude of the magnetic field.
01:27
In order for the protons to be in an undefected trajectory.
01:36
So here basically we have to find the field b.
01:43
Let's do this.
01:45
First of all, let's catch the direction of the force, which acts on the protons due to the electric field.
01:53
So this force f electric is along the field, which is to the right, along positive y...