00:01
To calculate the orientation of the major axis, we need to find the principal axis of the section.
00:07
So, the orientation of the major axis is perpendicular to the principal axis.
00:17
It is perpendicular, this is sign of perpendicular, ok perpendicular to the principal axis with the maximum moment of inertia, with maximum moment of inertia.
00:31
Now, the moment of inertia or second moment of area about the major and minor axis can be calculated using this formula i is equals to b h cube divide by 12.
00:49
Here b is the width of the beam and h is the height.
00:53
Now, the bending stress a can be calculated using this formula sigma is equals to mc divide by i.
01:01
Here m is the bending moment, c is the distance from the neutral axis to the outermost fiber and i is the area moment of inertia, ok.
01:13
So, now the orientation of the major axis.
01:17
So, the orientation can be calculated using this formula theta is equals to 0 .5 a tan 2 ixy and divide by ix minus iy, this is.
01:37
By this we can calculate the orientation.
01:40
Now, here ix and iy are the moment of inertia about x and y axis and ixy is the product of inertia.
01:48
Now, the moment of inertia, now we have to calculate the ix, iy and let us calculate it ix is equals to b h cube divide by 12 and iy is equals to b h cube divide by 12, ok...