00:01
In this problem we are given that there is a bicyclist and he's starting from rest and produces an angular acceleration of 1 .7 radiance per second square which is constant and this angular acceleration that's produced for the wheels which are having radius of 35 .5 centimeters which is equal to 0 .355 meters.
00:30
And we need to first determine the linear acceleration of this bicycle.
00:36
And we have to also determine the angular speed of the wheels of this bicycle provided that the bicycle reaches a speed of 11 .6 meter per second.
00:52
And then we have to determine in radiance how much the wheel has turned during this time.
01:01
So basically we have to determine the angular displacement.
01:04
And at the end, we have to find out the distance this bicycle has traveled in this time.
01:11
So let's take that distance as s, which is what we have to find as well.
01:15
So first we will use here this equation according to which the linear acceleration is our times angular acceleration.
01:22
So when we substitute the values here, we get a as 0 .355 times 1 .7.
01:30
And this comes out to be 0 .6 meter per second square.
01:35
So that's the linear acceleration.
01:37
And now to compute the angular speed, we just use this equation and rearrange.
01:42
So angular speed will be we by r.
01:45
So that will be 11 .6 divided by the radius, which is 0 .355.
01:50
And this comes out to be 32 .7 and this will be in radiance per second.
01:57
And then we have to determine the angle through which the wheel has turned...