A bike accelerates uniformly from rest to a speed of 10 m/s over a distance of 30 m. Determine the acceleration of the bike.
Added by Nick G.
Step 1
Step 1: Identify the given values: Initial velocity (u) = 0 m/s (bike starts from rest) Final velocity (v) = 10 m/s Distance (s) = 30 m Show more…
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A man starts from rest at $\mathrm{t}=0$, on a bike to cross a point $100 \mathrm{~m}$ away on a straight road in minimum time. In the last $15 \mathrm{~m}$ of the stretch, the speed is constant at $10 \mathrm{~m} \mathrm{~s}^{-1} .$ The constant acceleration or deceleration of the bike is $10 \mathrm{~m} \mathrm{~s}^{-2} .$ Match the columns. Column I (a) At $\mathrm{t}=1 \mathrm{~s}$ (b) At $\mathrm{t}=3 \mathrm{~s}$ (c) At $\mathrm{t}=5 \mathrm{~s}$ (d) At $\mathrm{t}=6 \mathrm{~s}$ Column II (p) stops deceleration (q) $\mathrm{v}=10 \mathrm{~m} \mathrm{~s}^{-1}$ (r) $\mathrm{v}=30 \mathrm{~m} \mathrm{~s}^{-1}$ (s) $\mathrm{v}=\mathrm{v}_{\max }$
A motorcycle is moving at $30 \mathrm{~m} / \mathrm{s}$ when the rider applies the brakes, giving the motorcycle a constant deceleration. During the $3.0 \mathrm{~s}$ interval immediately after braking begins, the speed decreases to $15 \mathrm{~m} / \mathrm{s}$. What distance does the motorcycle travel from the instant braking begins until the motorcycle stops?
Starting from rest, a bicyclist travels around a horizontal circular path, $\rho=10 \mathrm{m},$ at a speed of $v=\left(0.09 t^{2}+0.1 t\right) \mathrm{m} / \mathrm{s},$ where $t$ is in seconds. Determine the magnitudes of his velocity and acceleration when he has traveled $s=3 \mathrm{m}$
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