00:01
Hi there.
00:02
This is what we call a dilution problem where we have a stock solution of a certain concentration, and we are trying to make a less concentrated solution to use for a specific purpose.
00:17
So there is an equation that we use for dilution problems, and it is m1 times v1 equals m2 times v2, where one represents the stock solution, two represents the diluted solution, capital m is molarity, and capital v is the volume.
00:40
And this equation works because if we think about molarity, molarity is moles over volume.
00:47
So if we take moles over volume and multiply by volume, it gives us the number of moles.
00:52
However many moles we take out of the stock solution is the number of moles that will be in the diluted solution.
01:01
The only thing is that in the diluted solution, we're adding more volume to it so that that number of moles will be less dilute when it becomes molarity.
01:11
So let's see what we have here.
01:13
Our stock solution is 100 millimolar.
01:18
And we can just leave that as long as we have agreement on both sides of the arrow.
01:23
We do not have to convert that to molar...