A block attached to a spring oscillates in simple harmonic motion along the x-axis between the two extremes, x = 10 cm and x = 30 cm. The block goes from one extreme to the other in 0.25 s. Its amplitude and frequency are:
Added by Ahmad F.
Step 1
First, we need to find the amplitude of the oscillation. The amplitude is the maximum displacement from the equilibrium position. In this case, the equilibrium position is the midpoint between the two extremes, which is: (10 cm + 30 cm) / 2 = 20 cm The Show more…
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