A block is pulled across a horizontal surface with a force of 20N. The mass of the block is 5kg the block is traveling at a constant velocity. Calculate the force of friction acting on the block
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The block is moving at a constant velocity, which means the net force acting on the block is zero. This is because, according to Newton's first law of motion, an object will remain at rest or in uniform motion in a straight line unless acted upon by an external Show more…
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A block is pushed across a horizontal surface by the force shown. If the coefficient of kinetic friction between the block and the surface is 0.30, the applied force is F = 35 N at an angle below the horizontal of 30 degrees, and M = 5.0 kg, what is the magnitude of the acceleration of the block?
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ao A $2.5 \mathrm{~kg}$ block is initially at rest on a horizontal surface. A horizontal force $\vec{F}$ of magnitude $6.0 \mathrm{~N}$ and a vertical force $\vec{P}$ are then applied to the block (Fig. $6-17$ ). The coefficients of friction for the block and surface are $\mu_{s}=0.40$ and $\mu_{k}=0.25 .$ Determine the magnitude of the frictional force acting on the block if the magnitude of $\vec{P}$ is (a) $8.0 \mathrm{~N}$,(b) $10 \mathrm{~N}$, and $(\mathrm{c}) 12 \mathrm{~N}$
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