A block of copper with mass 0.600 kg is heated to 400. degrees Celsius from 260. degrees Celsius. The specific heat capacity of copper is 387 J/ (kg°C). The heat absorbed by the copper block is
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Step 1
First, we need to find the temperature change, which is the final temperature minus the initial temperature: ΔT = T_final - T_initial ΔT = 400°C - 260°C ΔT = 140°C Now, we can use the formula for heat absorbed, which is: Q = m × c × ΔT Show more…
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