A block of ice at 0 °C requires 33.40 kJ of heat to melt it. What is the mass of the ice? (Heat of fusion of ice = 334 J/g) 18.0 g 10.0 g 33.4 g 100. g 1.00 g 0.100 g
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1 kJ = 1000 J So, 33.40 kJ = 33.40 * 1000 = 33400 J The heat of fusion of ice is the amount of heat required to change 1 gram of ice at 0 °C to 1 gram of water at 0 °C without changing its temperature. It is given as 334 J/g. Show more…
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