Given that the force you applied is 91.0 N and the angle is 18.0°, the x-component of the force can be calculated as:
\( F_{\text{pull,x}} = F_{\text{pull}} \cdot \cos(18.0^\circ) \)
\( F_{\text{pull,x}} = 91.0 \, \text{N} \cdot \cos(18.0^\circ) \)
\(
Show more…