A block of ice with mass 2.00 $\mathrm{kg}$ slides 0.750 $\mathrm{m}$ down an inclined plane that slopes downward at an angle of $36.9^{\circ}$ below the horizontal. If the block of ice starts from rest, what is its final speed? You can ignore friction.
Added by Erik M.
Step 1
Given: Angle of inclination, $\theta = 36.9^\circ$, Distance, $d = 0.750$ m Use the formula: $h = d \sin(\theta)$ $h = 0.750 \times \sin(36.9^\circ)$ $h = 0.750 \times 0.6008$ $h = 0.450$ m Show more…
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A block of ice with mass 2.00 kg slides 0.750 m down an inclined plane that slopes downward at an angle of 36.9 degrees below the horizontal. If the block of ice starts from rest, what is its final speed? You can ignore friction.
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