"A block of mass 10 kg, moving in x direction with a constant speed of 10 ms– 1 , is subjected to a retarding force F = 0.1x J/m during its travel from x = 20 m to 30 m. Its final KE will be :"
Added by Shirlin S.
Step 1
Given: Mass (m) = 10 kg Initial velocity (v) = 10 m/s Initial Kinetic Energy (KE_initial) = 1/2 * m * v^2 KE_initial = 1/2 * 10 * 10^2 KE_initial = 1/2 * 10 * 100 KE_initial = 500 J Show more…
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Karan S.
A block of mass $10 \mathrm{~kg}$ is moving in $x$-direction with a constant speed of $10 \mathrm{~m} \mathrm{~s}^{-1}$. It is subjected to a retarding force $F_{r}=-0.1 x \mathrm{~J} \mathrm{~m}^{-1}$ during its travel from $x=20 \mathrm{~m}$ to $x=30 \mathrm{~m}$. Its final kinetic energy will be (a) $250 \mathrm{~J}$ (b) $275 \mathrm{~J}$ (c) $450 \mathrm{~J}$ (d) $475 \mathrm{~J}$
A block of mass $2 \cdot 00 \mathrm{~kg}$ moving at a speed of $10^{\circ} 0 \mathrm{~m} / \mathrm{s}$ accelerates at $3 \cdot 00 \mathrm{~m} / \mathrm{s}^{2}$ for $5 \cdot 00 \mathrm{~s}$. Compute its final kinetic energy.
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