A block of mass 1.0 kg slides on a rough track ABC, shown in the figure. If the block starts from rest at point A, and its speed at point C is 10 m/s, then the work (in J) done by the frictional force is: A. -218 B. -188 C. 100 D. -146 E. -167 A 60 m C 40 m B
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0 kg Acceleration due to gravity, g = 9.8 m/s^2 Height at point A, h1 = 60 m Potential energy at point A, PE1 = mgh1 PE1 = 1.0 kg * 9.8 m/s^2 * 60 m PE1 = 588 J Show more…
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A block of mass $10 \mathrm{~kg}$ slides down a rough slope which is inclined at $45^{\circ}$ to the horizontal. The coefficient of sliding friction is $0.30$. When the bloek has slide $5 \mathrm{~m}$, the work done on the block by the force of friction is nearly (a) $115 \mathrm{~J}$ (b) $75 \sqrt{2} \mathrm{~J}$ (c) $321.4 \mathrm{~J}$ (d) $-321.4 \mathrm{~J}$
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A 4.0-kg block starts from rest and slides 5.0 m down a plane inclined at 60 degrees to the horizontal. The coefficient of kinetic friction between the surface and the block is 0.20. The work done by friction on the block is A) 98.0 J B) 19.6 J C) 3.92 J D) 3.40 J E) 64.0 J
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