4. A block of mass 1.20 kg is on a rough horizontal surface. A force of 12 N is applied to the block and it accelerates 4.0 ms^-2. What is the magnitude of the frictional force acting on the block? 16.8 N 2.4 N 7.2 N 3.6 N
Added by Ivan L.
Close
Step 1
This can be calculated using Newton's second law of motion, which states that the force is equal to the mass of the object multiplied by its acceleration. Force = mass * acceleration = 1.20 kg * 4.0 m/s^2 = 4.8 N This is the net force acting on the block. Show more…
Show all steps
Your feedback will help us improve your experience
Pranay Shrivastava and 84 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 2 kg block slides on a rough horizontal surface. A force (P = 4 N) is applied to the block as shown. The magnitude of the block's acceleration is 1.2 m/s2. What is the magnitude of the force of friction acting on the block? answer 1.6
Abid H.
A force of $40.0 \mathrm{N}$ accelerates a 5.0 -kg block at $6.0 \mathrm{m} / \mathrm{s}^{2}$ along a horizontal surface. a. How large is the frictional force? b. What is the coefficient of friction?
Forces in Two Dimensions
Force and Motion in Two Dimensions
ao A $2.5 \mathrm{~kg}$ block is initially at rest on a horizontal surface. A horizontal force $\vec{F}$ of magnitude $6.0 \mathrm{~N}$ and a vertical force $\vec{P}$ are then applied to the block (Fig. $6-17$ ). The coefficients of friction for the block and surface are $\mu_{s}=0.40$ and $\mu_{k}=0.25 .$ Determine the magnitude of the frictional force acting on the block if the magnitude of $\vec{P}$ is (a) $8.0 \mathrm{~N}$,(b) $10 \mathrm{~N}$, and $(\mathrm{c}) 12 \mathrm{~N}$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD