A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional force?
Added by Eddie H.
Step 1
Given: mass (m) = 5 kg, acceleration due to gravity (g) = 10 m/s^2 Normal force (N) = m * g N = 5 kg * 10 m/s^2 N = 50 N ** Show more…
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