A block of mass m = 0.1 kg is released from a height of 4 m on a curved smooth surface. On the horizontal surface, path AB is smooth and path BC offers coefficient of friction m = 0.1. If the impact of block with the vertical wall at C be perfectly elastic, the total distance covered by the block on the horizontal surface before coming to rest will be:
Added by Benzamin G.
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The potential energy is given by the formula: \[ \text{PE} = m \cdot g \cdot h \] where \( m = 0.1 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), and \( h = 4 \, \text{m} \). \[ \text{PE} = 0.1 \cdot 9.8 \cdot 4 = 3.92 \, \text{J} \] Show more…
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A block of mass $m=0.1 \mathrm{~kg}$ is released from a height of $4 \mathrm{~m}$ on a curved smooth surface. On the horizontal surface, path $A B$ is smooth and path $B C$ offers coefficient of friction $\mu=0.1$. If the impact of block with the vertical wall at $C$ be perfectly elastic, the total distance covered by the block on the horizontal surface before coming to rest will be: (take $g=10 \mathrm{~m} / \mathrm{s}^{2}$ ) (A) $29 \mathrm{~m}$ (B) $49 \mathrm{~m}$ (C) $59 \mathrm{~m}$ (D) $109 \mathrm{~m}$
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