Question

A block of mass m = 14.5 kg rests on an inclined plane with a coefficient of static friction of ?s = 0.17 between the block and the plane. The inclined plane is L = 6.2 m long and it has a height of h = 3.2 m at its tallest point. What is the magnitude of the normal force, FN in newtons, that acts on the block? What is the component of the force of gravity along the plane, Fgx in newtons?

          A block of mass m = 14.5 kg rests on an inclined plane with a coefficient of static friction of ?s = 0.17 between the block and the plane. The inclined plane is L = 6.2 m long and it has a height of h = 3.2 m at its tallest point.

What is the magnitude of the normal force, FN in newtons, that acts on the block?

What is the component of the force of gravity along the plane, Fgx in newtons?

A block of mass m = 14.5 kg rests on an inclined plane with a coefficient of static friction of ?s = 0.17 between the block and the plane. The inclined plane is L = 6.2 m long and it has a height of h = 3.2 m at its tallest point.

What is the magnitude of the normal force, FN in newtons, that acts on the block?

What is the component of the force of gravity along the plane, Fgx in newtons?

Added by Shannon G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/13/2022

Step 1

2}{6.2}\right) = 31.1^\circ \] Show more…

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A block of mass m = 14.5 kg rests on an inclined plane with a coefficient of static friction of μs = 0.17 between the block and the plane. The inclined plane is L = 6.2 m long and it has a height of h = 3.2 m at its tallest point. What is the magnitude of the normal force, FN in newtons, that acts on the block? What is the component of the force of gravity along the plane, Fgx in newtons?