00:01
Hello everyone we are going to understand this question here given mass of block mass of smaller block that is represented by small m which is given 15 kg and height of block is given 5 .0 meter mass of larger block mass of larger block capital m is equal to 30 kg spring constant spring constant k is equal to 500 newton per meter now in part a we have to find the speed after the sorry in the part a we have to find the speed of the blocks after the after collision so here now applying the conservation of energy applying conservation of energy conservation of energy so initial energy of the block that will be m g h so m into g into h is equal to final speed when it will reach to the ground it has the maximum kinetic energy that is half mv square so after solving we will get v is equal to square root of 2h upon now substituting the value in this, so here we can write 2 into value of h that is 5 meter upon value of g that is 9 .8.
02:41
So after doing the calculation we will get f is equal to 7 square root 2.
02:49
Sorry here we did a calculation mistake here v will be square root of 2 g h b is equal to square root of 2 g into h.
03:02
So here 2 into value of g is 9 .8 and height of the block b, the initial height of the block that is given 5 meter.
03:15
So after doing the calculation we will get 7 root 2.
03:19
Now again applying the conservation of momentum.
03:23
Now applying conservation of momentum.
03:31
Conservation of momentum.
03:35
So here it will be m into v is equal to after collision it is getting stick together.
03:55
So here we can write v is equal to mv upon small m plus capital m so here small v we have calculated 7 root 2 into m that is 15 upon 15 plus 30...