A block of mass m = 50 kg moves on a rough horizontal surface with a coefficient of kinetic friction μ = 0.5. The traveled distance is 20 m. How much work is done by the friction force?
Added by Jose Maria M.
Step 1
Given that the coefficient of kinetic friction is μ = 0.5 and the normal force is equal to the weight of the block, which is F_N = mg, where g is the acceleration due to gravity (9.8 m/s^2). Friction force (F_friction) = μ * F_N F_friction = 0.5 * 50 kg * 9.8 Show more…
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