Question

A block of mass m1 = 1.70 kg moving at v1 = 2.00 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.300 kg. The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg, which is initially at rest. The three blocks then move, stuck together, with speed v3. (Figure 1) Assume that the blocks slide without friction. Part A. Find v2/v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision. Part B. Find v3/v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions.

          A block of mass m1 = 1.70 kg moving at v1 = 2.00 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.300 kg. The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg, which is initially at rest. The three blocks then move, stuck together, with speed v3. (Figure 1) Assume that the blocks slide without friction.

Part A. Find v2/v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision.

Part B. Find v3/v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions.

Added by Stephen G.

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