A block of mass m1=2.2 kg is placed on an incline with an angle of 25 degrees. if the block slides down the incline at a constant speed, what is the coefficient of kinetic friction
Added by Kenneth D.
Step 1
2 kg and g = 9.81 m/s^2. Plugging in the values, we get N = 2.2 kg * 9.81 m/s^2 * cos(25) ≈ 19.98 N. Show more…
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