A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction
Added by Arun B.
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5 * m * u^2 KE = 0.5 * 1 * (20)^2 KE = 0.5 * 1 * 400 KE = 200 J Show more…
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A body of mass $1 \mathrm{~kg}$ is thrown upwards with a velocity $20 \mathrm{~m} / \mathrm{s}$. It momentarily comes to rest after a height $18 \mathrm{~m}$. How much energy is lost due to air friction. $(\mathrm{g}=10 \mathrm{~m} / \mathrm{s} 2)$ (A) $20 \mathrm{~J}$ (B) $30 \mathrm{~J}$ (C) $40 \mathrm{~J}$ (D) $10 \mathrm{~J}$
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