A body of mass 1 kg is dropped from a height of 5 m onto the ground. If the body penetrates 2 cm into the ground, the average resistance offered by the ground onto the body is (g = 10 m/s).
Added by Melanie L.
Step 1
\[ \text{PE} = mgh \] where \( m = 1 \, \text{kg} \), \( g = 10 \, \text{m/s}^2 \), and \( h = 5 \, \text{m} \). \[ \text{PE} = 1 \times 10 \times 5 = 50 \, \text{J} \] Show more…
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