A body of mass 5 Kg initially at rest is moved by a horizontal force of 2 N on a smooth horizontal surface. The work done by the force in 10 s is A. 20 J B. 30 J C. 40 J D. 60 J
Added by Donald C.
Step 1
Given: Mass (m) = 5 kg Force (F) = 2 N Acceleration (a) = F / m Acceleration (a) = 2 N / 5 kg Acceleration (a) = 0.4 m/s^2 Show more…
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