A body of mass m starting from rest is acted on by a force producing a velocity v = √(k × s), where k is a constant and s is displacement. The work done by the force in the first t seconds is: A. m^2k^2t^2/8 B. mk^2t^2/4 C. mk^2t^2/8 D. m^2k^2t^4
Added by Patrick O.
Step 1
We can square both sides to get rid of the square root: v^2 = k × s Now, we know that velocity is the derivative of displacement with respect to time, so we can write: v = ds/dt We can substitute the expression for v^2 back into this equation: (ds/dt)^2 = k × Show more…
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