"A body of mass of 100g is attached to a 1m long string and it is revolving in a vertical circle. When the string makes an angle of 60o with the vertical then its speed is 2 m /s . The tension in the string at 60o ļ± ļ½ will be"
Added by Barry B.
Step 1
1kg Acceleration due to gravity, g = 9.8 m/s^2 Gravitational force, Fg = m * g Fg = 0.1 * 9.8 Fg = 0.98 N Show moreā¦
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A body of mass of $100 \mathrm{~g}$ is attached to a $1 \mathrm{~m}$ long string and it is revolving in a vertical circle. When the string makes an angle of $60^{\circ}$ with the vertical then its speed is $2 \mathrm{~m} / \mathrm{s}$. The tension in the string at $\theta=60^{\circ}$ will be (a) $89 \mathrm{~N}$ (b) $0.89 \mathrm{~N}$ (c) $8.9 \mathrm{~N}$ (d) $0.089 \mathrm{~N}$
Centripetal force: $F=m v^{2} / r$ A horizontal string whirls a 1-kg can in a circle of radius 2 m with a speed of 2 m/s. Calculate the tension in the string.
A ball of mass m=0.22kg is being swung in a vertical circle on a string, as shown in the given figure. At the instant it is directly above the center of the circle it is making, its speed is v=2.7ms. The string has negligible mass, and its length is . What is the tension, T, in the string at the instant the ball is at the top of its circle?
Satish K.
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