00:01
So here we have to write the expression for power input into the power.
00:04
So power input will be equals to v, multiplied by the del of p divided by the n of mechanism.
00:10
So, v from here will be equals to nita, multiplied by the p divided by the dell of p.
00:16
So we are having the value of nita.
00:18
That is 5 multiplied by the 10 raise to the battery, power pressure is 0 .78 divided by the del p.
00:24
That is 1 ,000, multiply by the 9 .81, multiply by the 0 .01.
00:29
8.
00:30
So from here value of volume will become equal to 22 .08 meter cube per second.
00:36
Now we have to determine the density of air.
00:38
So row of air will be equals to p divided by the r of t.
00:42
So that will be close to 1 .2 multiply by the 10 to the power 5 divided by the 287 plus 273 plus 17 that was in kilogram per meter cube.
00:54
So from here row of a will be equals to 1 .44 kilogram...