00:01
Here, given that, the input voltage is given, vi is equal to 5 volt.
00:07
The output voltage is given which is equal to 15 volt.
00:12
The output current is given which is 0 .5 amoeia.
00:17
The frequency is given 25 kilohertz, which means 25 into 10 power 3 hertz.
00:24
The value of inductance is given l is equal to 150 micro -henry, which means 150 into 10 power minus 6 -henry.
00:32
The capacitance is given 220 microfaird which means 220 into 10 power minus 6 ferret.
00:40
So this is the circuit diagram of a boost converter.
00:46
So the circuit diagram of a boost converter is as shown here.
00:52
Here in the first part in the a part we need to calculate the duty cycle.
00:57
So by inductor volt second balance we have the following equation.
01:08
By inductor volt second balance, the equation is input voltage into duty cycle into t is equal to vi minus v0 into 1 minus d into t.
01:21
Upon solving, canceling and solving we get v0 by vi is equal to 1 divided by 1 minus d or from here we have to calculate the duty cycle d.
01:33
D is equal to 1 minus input voltage divided by output voltage.
01:37
So this is equal to 1 minus input voltage is 5 volt divided by output voltage is equal to 15 volt.
01:44
Upon solving we get the value of duty cycle d is equal to 0 .866666.
01:52
So here this will be the value of duty cycle capital letter d.
01:57
Now in the next part, in the b part, here we need to calculate inductor ripple current.
02:05
Inductor ripple current is to be calculated.
02:08
So the formula for inductor ripple current is given by inductor ripple current delta il is equal to input voltage into duty cycle d divided by the inductance l into the frequency fs, which is equal to the input voltage is 5 volt into duty cycle we have just now found out 0 .8 triple 6 divided by the inductance which is given in the question as 150 micro henry.
02:36
So 150 into 10 power minus 600 into the frequency 25 kilohertz...