00:01
The initial temperature t1 is 50 degrees centigrade where the final temperature t2 is 4 degrees centigrade.
00:09
And the diameter is given as diameter is 6 cm or it will be 0 .06 meters and the length of the bottle is 20 cm that is 0 .2 meter.
00:32
Here the heat transfer rate, heat transfer rate q will be equal to age times a multiplied with the t1 minus of the t2, the changing temperature where a is the area of the bottle, area of bottle.
00:59
T1 minus of the t2, that is the changing temperature, 50 minus 4 is equal.
01:04
To 40 to 60 degrees centigrade and age is heat transfer coefficient coefficient from these equations we conclude over here that the area and the changing temperature is remaining constant that means higher the higher the heat transfer coefficient higher is the heat transfer rate as heat transfer rate as here's the area and delta t remains constant is same in both horizontal and vertical placement of the bottle placement of bottle.
02:25
Heat transfer coefficient, the value of the h can be calculated for calculated from nozzle number equations.
02:39
Nostled number equations.
02:43
So let's know what is this nussle number equation.
02:46
Nu will be equal to h d divided by that is equal to zr, pr to the power n.
02:58
This is for horizontal position, horizontal position of the bottle.
03:06
And the nothing of the equation nu will be equal to h, l divided by k, it will be twice to gr, pr, to the power n...