A box contains 7 red balls 4 green balls and 3 blue balls...

A box contains 7 red balls, 4 green balls, and 3 blue balls. You pull 2 balls from the box (one at a time) WITHOUT replacement. **LEAVE ALL ANSWERS AS FRACTIONS** Find the probability of the following: a.) P(Red on 1st ball AND Red on 2nd ball) = b.) P(Green on 1st ball AND Red on 2nd ball) = c.) P(Blue on 1st ball AND Green on 2nd ball) = d.) What is the probability of drawing 2 green balls in your 2 pulls? e.) What is the probability of selecting a red ball on your second pull, given a red ball was already selected on the first pull?

Transcript

00:01 Okay, and your question you're told, we have a box containing the following colored balls, seven are red, four or green, three are blue.

00:08 That's a total of 14.

00:09 You're asked to find the following probabilities and leave your answers as fractions.

00:14 The one key piece of information here that we were told is a ball is drawn, and then a second is drawn without replacing the first ball.

00:24 Okay, so probability of a red, then a red.

00:26 The first probability would be for red seven out of 14.

00:33 There are seven reds out of 14 total.

00:36 We then multiply that to probability that we get a red again.

00:40 Now, there would only be six reds left, and there would only be 13 balls left.

00:46 Okay, so we want to go ahead and multiply them.

00:49 I'm going to simplify before i multiply.

00:51 7 .14th would simplify to a half, giving me 6 over 26, or, 3 out of 13.

01:02 So 3 out of 13 is the probability for red than a red.

01:07 A green than a red, there are four greens out of 14.

01:13 We would multiply that by, there are seven reds left out of 13.

01:20 To simplify this one before we multiply, we would take out the 7, make it a 1, and the 14 make it a 2.

01:28 Giving a i can cross out the four make it a two and the two a one giving us a two thirteenth probability and again if you're unsure on how i'm setting up probability probability is favorable what we want over possible okay so let's move on to part c blue then green there are three blues out of the 14 that we would be drawing from.

02:01 And then for the second draw, we want a green...

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