A box is held at the top of a ramp the ramp is 10 meters...

A box is held at the top of a ramp. The ramp is 10 meters high and has an incline of 30 degrees above the horizontal. The box has a mass of 20 kg and the coefficient of friction between the box and the ramp is 0.5. The box is released to slide down the ramp. Answer the following questions in this section. a. What is the magnitude of the Normal Force? b. What is the value of the Frictional Force? c. What is the magnitude of the acceleration in the X-Direction? d. What is the initial potential energy of the box? e. What is the final potential energy of the box when it reaches the bottom of the ramp?

Transcript

00:01 Hi, in this question the height of the ramp is given as 10 meters, that is h is equal to 10 meters.

00:09 Then the angle made by the ramp with respect to horizontal is given as 30 degrees.

00:16 Theta is equal to 30 degrees.

00:18 The mass of the box is given as m is equal to 20 kg.

00:27 Then the coefficient of friction mu is given as 0 .5.

00:33 We need to determine the normal reaction n, the frictional force, ff, then we need to find the acceleration of the box, then we need to find the initial potential energy.

01:01 Also, we need to find the final potential energy, uf.

01:05 So these are all the parameters we need to determine.

01:10 First of all, let us determine the normal reaction.

01:15 The normal reaction, n will be equal to mg.

01:23 Mg is the weight of the box, multiply with cost theta.

01:29 This is one of the components of the weight, which will be acting in the opposite direction of the normal reaction.

01:37 Now let us plug the given values here and determine the normal reaction.

01:42 Mass of the box is 20 kg.

01:45 Acceleration due to gravity is 9 .8 meter per second square.

01:50 Cos 30.

01:52 On calculation we obtained the normal reaction n is equal to 169 .74 newtons.

02:05 Now let us go into the subdivision b.