Question

A box of mass M = 5 kg is sliding down a rough inclined plane with a constant velocity of v = 6.8 m/s, as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide? The angle of the incline $\theta$ is 35 degrees.

Name: A box of mass M = 5 kg is sliding down a rough inclined plane with a constant velocity of v = 6.8 m/s, as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide? The angle of the incline θ is 35 degrees.
Uploaded: 2021-12-24T09:13:46-08:00
Duration: 3 min 26 s
Channel: Jagjit Singh Chander
Description: A box of mass M = 5 kg is sliding down a rough inclined plane with a constant velocity of v = 6.8 m/s, as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide? The angle of the incline θ is 35 degrees.

          A box of mass M = 5 kg is sliding down a rough inclined plane with a constant velocity of v = 6.8 m/s, as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide? The angle of the incline $\theta$ is 35 degrees.

A box of mass M = 5 kg is sliding down a rough inclined plane with a constant velocity of v = 6.8 m/s, as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide? The angle of the incline θ is 35 degrees.

Added by Kathleen W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Jagjit Singh Chander

12/24/2021

Step 1

The gravitational force acting on the box can be calculated using the formula: F_gravity = m * g where m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s^2). Given that the mass of the box is M = 5 kg, the gravitational Show more…

Show all steps

Thanks for your feedback!

A box of mass M=5 kg is sliding down a rough inclined plane with a constant velocity of v=6.8 m/s.as in the figure below. There is friction between the incline and the box. What is the work done by the frictional force during a 4 second interval of the boxes slide?Theangle of the incline is35degrees