00:01
In this problem, we're given the volume of a box a length and a width, and we want to express the height of the box.
00:06
So you have to divide the length and width into the volume to find that height.
00:10
So let's do it.
00:11
Let's first divide this 2x plus 3.
00:13
Dividing 2x plus 3 would be easy to do synthetically if we didn't have 2x with 3 and instead x plus something.
00:19
So let's rewrite this as 2 times x plus 3 over 2 and divide a 2 in first.
00:25
So if we divide it 2 in first, we get 6x cubed plus 10.
00:30
X squared minus 21 over 2x minus 18.
00:35
So now let's divide an x plus 3 over 2.
00:40
So that's our first step.
00:43
Now let's take our k, which is going to be negative 3 over 2, put it in the corner and bring our coefficients down.
00:48
So we'll have 6, 10, negative 21 over 2, and negative 18.
00:54
Bring the 6 down.
00:56
6 times negative 3 over 2 is going to be negative 9.
00:59
10 plus negative 9 is going to be 1 .000.
01:01
1 times negative 3 over 2 is going to be negative 3 over 2.
01:06
Negative 3 over 2 plus negative 21 over 2.
01:09
It's going to be negative 24 over 2 or negative 12.
01:12
Negative 12 times negative 3 over 2 is going to give us a positive 18...