00:01
So, here in this question we are considering a three -sided fillet -wallet lap which is joint composite of the two plates where the force is given that is equal to 7500 newton and we are considering about e70 of xx where the value of s of y is equal to 380 that is in the mega pascal.
00:22
So, here we are considering about a welding point for here.
00:24
So, the centroid from here is calculated as centroid at the distance is calculated as 90 which is multiplied by the 45 that is multiplied by the y become equals to 120 which is multiplied by 60 that is multiplied by 140.
00:39
So, solving the term from here we get the value of y that become equals to 89 .6 millimeter.
00:44
Now say the centroid centroid is at point x millimeter away from the weld that is at point w3.
00:55
So, this from here is equals to 90 plus 140 plus 120 multiplied by the x become equals to 90 multiplied by the 89 .6 plus 120 which is multiplied by the 50 .4 plus 140 which is multiplied by the 0.
01:11
So, solving the term we get the value of x that become equals to 40 .92 millimeter.
01:17
So, this is the value of x and from the given figure we can say that we are having the value of r1 that is equals to under root of 90 minus 40 .92 to its whole square plus 89 .6 to its whole square.
01:31
So, the value of r1 from here is equals to 102 .45 that is in millimeter.
01:36
This is the value of the r1 and the area from here is given as a1 that is equals to 90 which is multiplied by 6 that is equals to 540 millimeter square in the same way the value of a2 become equals to 120 which is multiplied by 6 that is equals to 720 millimeter square and the value of a3 become equals to 140 which is multiplied by 6 that is equals to 840 millimeter to its whole square.
02:01
So, the value of a is equals to a1 plus a2 plus a3...