00:01
To determine the ph of the solution, the buffer solution, we can use the henderson -hasselbalch equation, where ph is going to be equal to pka, which is the negative log of the ka value, 1 .8 times 10 to the negative 6, plus the log of, we could use the moles of the base over moles of the acid, or molarity base over molarity acid.
00:28
In many cases, as in this case, it's going to be easier to just use moles.
00:33
So the moles of the base is the 2 moles, and the moles of the acid is the 0 .6 moles, and we get a ph of 6 .27.
00:54
Now, they've given us the incorrect ka value, but i'm using what they gave us.
01:00
For acetic acid, it's actually 1 .8 times 10 to the negative 5, not 1 .8 times 10 to the negative 6.
01:08
Then for the second scenario, ph again will be equal to pka, which will be the negative log of the ka value in this case, which is 5 .6 times 10 to the negative 11, and then we'll add to that the log of, so we're preparing this by taking 15 grams of the base and 15 grams of the acid.
01:37
So we could simply convert the grams into moles, so 15 .0 grams of the base, which is sodium carbonate.
01:51
The molar mass of sodium carbonate is the mass of 2 moles sodium and 1 mole carbon, 3 moles oxygen gives us 105 .99 grams...